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Method `/()
- Method
`/
mixed `/(object arg1, mixed arg2)
mixed `/(mixed arg1, object arg2)
array(string) `/(string arg1, int arg2)
array(string) `/(string arg1, float arg2)
array(array) `/(array arg1, int arg2)
array(array) `/(array arg1, float arg2)
array(string) `/(string arg1, string arg2)
array(array) `/(array arg1, array arg2)
float `/(float arg1, int|float arg2)
float `/(int arg1, float arg2)
int `/(int arg1, int arg2)
mixed `/(mixed arg1, mixed arg2, mixed ... extras) - Description
Division/split.
Every expression with the / operator becomes a call to
this function, i.e. a/b is the same as
predef::`/(a,b).
- Returns
If there are more than two arguments, the result will be
`/(`/(arg1 , arg2 ), @extras ).
If arg1 is an object that implements lfun::`/() , that
function will be called with arg2 as the single argument.
If arg2 is an object that implements lfun::``/() , that
function will be called with arg1 as the single argument.
Otherwise the result will be as follows:
arg1 can have any of the following types:
| string | arg2 can have any of the following types:
| int|float | The result will be and array of arg1 split in segments
of length arg2 . If arg2 is negative the splitting
will start from the end of arg1 .
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| string | The result will be an array of arg1 split at each
occurrence of arg2 . Note that the segments that
matched against arg2 will not be in the result.
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| array | arg2 can have any of the following types:
| int|float | The result will be and array of arg1 split in segments
of length arg2 . If arg2 is negative the splitting
will start from the end of arg1 .
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| array | The result will be an array of arg1 split at each
occurrence of arg2 . Note that the elements that
matched against arg2 will not be in the result.
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| float|int | The result will be arg1 / arg2 . If both arguments
are int, the result will be truncated to an int. Otherwise the
result will be a float.
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- Note
Unlike in some languages, the function f(x) = x/n (x and n integers)
behaves in a well-defined way and is always rounded down. When you
increase x, f(x) will increase with one for each n:th increment. For
all x, (x + n) / n = x/n + 1; crossing
zero is not special. This also means that / and % are compatible, so
that a = b*(a/b) + a%b for all a and b.
- See also
`%
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`->=()