Method `*()

Method `*

mixed `*(mixed arg1)
mixed `*(object arg1, mixed arg2, mixed ... extras)
mixed `*(mixed arg1, object arg2)
array `*(array arg1, int arg2)
array `*(array arg1, float arg2)
string `*(string arg1, int arg2)
string `*(string arg1, float arg2)
string `*(array(string) arg1, string arg2)
array `*(array(array) arg1, array arg2)
float `*(float arg1, int|float arg2)
float `*(int arg1, float arg2)
int `*(int arg1, int arg2)
mixed `*(mixed arg1, mixed arg2, mixed ... extras)

Description

Multiplication/repetition/implosion.

Every expression with the * operator becomes a call to this function, i.e. a*b is the same as predef::`*(a,b). Longer * expressions are normally optimized to one call, so e.g. a*b*c becomes predef::`*(a,b,c).

Returns

If there's a single argument, that argument will be returned.

If the first argument is an object that implements lfun::`*() , that function will be called with the rest of the arguments.

If there are more than two arguments, the result will be `*(`*(arg1 , arg2 ), @extras ).

If arg2 is an object that implements lfun::``*() , that function will be called with arg1 as the single argument.

Otherwise the result will be as follows:

arg1 can have any of the following types:

array

arg2 can have any of the following types:

`int\|float`	The result will be arg1 concatenated arg2 times.
`string\|array`	The result will be the elements of arg1 concatenated with arg2 interspersed.

string

The result will be arg1 concatenated arg2 times.

int|float

The result will be arg1 * arg2 , and will be a float if either arg1 or arg2 is a float.

Note

In Pike 7.0 and earlier the multiplication order was unspecified.