std::is_fundamental
From cppreference.com
Defined in header
<type_traits>
|
||
template< class T >
struct is_fundamental; |
(since C++11) | |
If T
is a fundamental type (that is, arithmetic type, void, or nullptr_t), provides the member constant value
equal true. For any other type, value
is false.
Contents |
[edit] Template parameters
T | - | a type to check |
[edit] Helper variable template
template< class T >
constexpr bool is_fundamental_v = is_fundamental<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value
[static]
|
true if T is a fundamental type , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator()
(C++14)
|
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
[edit] Possible implementation
template< class T > struct is_fundamental : std::integral_constant< bool, std::is_arithmetic<T>::value || std::is_void<T>::value || std::is_same<std::nullptr_t, typename std::remove_cv<T>::type>::value > {}; |
[edit] Example
Run this code
#include <iostream> #include <type_traits> class A {}; int main() { std::cout << std::boolalpha; std::cout << std::is_fundamental<A>::value << '\n'; std::cout << std::is_fundamental<int>::value << '\n'; std::cout << std::is_fundamental<int&>::value << '\n'; std::cout << std::is_fundamental<int*>::value << '\n'; std::cout << std::is_fundamental<float>::value << '\n'; std::cout << std::is_fundamental<float&>::value << '\n'; std::cout << std::is_fundamental<float*>::value << '\n'; }
Output:
false true false false true false false
[edit] See also
(C++11)
|
checks if a type is compound type (class template) |
(C++11)
|
checks if a type is arithmetic type (class template) |
(C++11)
|
checks if a type is void (class template) |
(library fundamentals TS)
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variable template alias of std::is_fundamental::value (variable template) |