std::is_compound
From cppreference.com
Defined in header
<type_traits>
|
||
template< class T >
struct is_compound; |
(since C++11) | |
If T
is a compound type (that is, array, function, object pointer, function pointer, member object pointer, member function pointer, reference, class, union, or enumeration, including any cv-qualified variants), provides the member constant value
equal true. For any other type, value
is false.
Contents |
[edit] Template parameters
T | - | a type to check |
[edit] Helper variable template
template< class T >
constexpr bool is_compound_v = is_compound<T>::value; |
(since C++17) | |
Inherited from std::integral_constant
Member constants
value
[static]
|
true if T is a compound type , false otherwise (public static member constant) |
Member functions
operator bool |
converts the object to bool, returns value (public member function) |
operator()
(C++14)
|
returns value (public member function) |
Member types
Type | Definition |
value_type
|
bool
|
type
|
std::integral_constant<bool, value> |
[edit] Notes
Compound types are the types that are constructed from fundamental types. Any C++ type is either fundamental or compound.
[edit] Possible implementation
template< class T > struct is_compound : std::integral_constant<bool, !std::is_fundamental<T>::value> {}; |
[edit] Example
Run this code
Output:
T is compound T is not a compound
[edit] See also
(C++11)
|
checks if a type is fundamental type (class template) |
(C++11)
|
checks if a type is scalar type (class template) |
(C++11)
|
checks if a type is object type (class template) |
(C++11)
|
checks if a type is an array type (class template) |
(library fundamentals TS)
|
variable template alias of std::is_compound::value (variable template) |