default initialization

 

C++

Language

Standard library headers

Concepts

Utilities library

Strings library

Containers library

Algorithms library

Iterators library

Numerics library

Input/output library

Localizations library

Regular expressions library (C++11)

Atomic operations library (C++11)

Thread support library (C++11)

Technical Specifications

 

C++ language

 

Initialization

Initializer

Default initialization

Value initialization

Direct initialization

Copy initialization

List initialization

Aggregate initialization

Reference initialization

Static initialization

Zero initialization

Constant initialization

Dynamic non-local initialization

Ordered dynamic initialization

Unordered dynamic initialization

Class member initialization

Member initializer list

in-class brace-or-equal initializer

 

This is the initialization performed when a variable is constructed with no initializer.

Syntax

T object ;	(1)
new T ; new T ( ) ; (until c++03)	(2)

Explanation

Default initialization is performed in three situations:

1) when a variable with automatic, static, or thread-local storage duration is declared with no initializer.

2) when an object with dynamic storage duration is created by a new-expression with no initializer or when an object is created by a new-expression with the initializer consisting of an empty pair of parentheses (until C++03).

3) when a base class or a non-static data member is not mentioned in a constructor initializer list and that constructor is called.

The effects of default initialization are:

• If T is a non-POD (until C++11) class type, the constructors are considered and subjected to overload resolution against the empty argument list. The constructor selected (which is one of the default constructors) is called to provide the initial value for the new object.
• If T is an array type, every element of the array is default-initialized.
• Otherwise, nothing is done: the objects with automatic storage duration (and their subobjects) are initialized to indeterminate values.

Only (possibly cv-qualified) non-POD class types (or arrays thereof) with automatic storage duration were considered to be default-initialized when no initializer is used. Scalars and POD types with dynamic storage duration were considered to be not initialized (since C++11, this situation was reclassified as a form of default initialization).	(until C++11)
Prior to C++03 (which introduced value initialization), the expression new T() as well as a member initializer naming a base or a member with the initializer in the form of an empty pair of parentheses was classified as default initialization, but specified zero initialization for non-class types.	(until C++03)

If T is a cv-qualified type, its cv-unqualified version is used for the purpose of default-initialization.

(until C++11)

Use of an indeterminate value obtained by default-initializing a non-class variable of any type is undefined behavior, except in the following cases: if the indeterminate value of unsigned narrow character type is assigned to another variable with unsigned narrow character type (the value of the variable becomes indeterminate, but the behavior is not undefined) if the indeterminate value of unsigned narrow character type is used to initialize another variable with unsigned narrow character type if the indeterminate value of unsigned narrow character type results from the second or third operand of a conditional expression the right operand of the comma operator the operand of a cast or conversion to an unsigned narrow character type a discarded-value expression int f(bool b) { int x; // value of x is indeterminate int y = x; // undefined behavior unsigned char c; // value of c is indeterminate unsigned char d = c; // OK, value of d is indeterminate int e = d; // undefined behavior return b ? d : 0; // undefined behavior if b is true }

(since C++14)

Notes

Default initialization of non-class variables with automatic and dynamic storage duration produces objects with indeterminate values (static and thread-local objects get zero initialized)

If T is a const-qualified type, it must be a class type with a user-provided default constructor.

Reference cannot be default-initialized.

Example

Run this code

#include <string>
 
struct T1 {};
 
class T2
{
    int mem;
 public:
    T2() {} // "mem" not in initializer list
};
 
int n; // A two-phase initialization is done
       // In the first phase, zero initialization initializes n to zero
       // In the second phase, default initialization does nothing, leaving n being zero
 
int main()
{
    int n;            // non-class: the value is indeterminate
    std::string s;    // calls default ctor, the value is "" (empty string)
    std::string a[2]; // calls default ctor, creates two empty strings
//  int& r;           // error: default-initializing a reference
//  const int n;      // error: const non-class type
//  const T1 t1;      // error: const class type with implicit default ctor
    T1 t1;            // ok, calls implicit default ctor
    const T2 t2;      // ok, calls the user-provided default ctor 
                      // t2.mem is default-initialized (to indeterminate value)
}

See also

• direct initialization
• copy initialization
• list initialization