const_cast conversion
From cppreference.com
Converts between types with different cv-qualification.
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[edit] Syntax
const_cast < new_type > ( expression )
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Returns a value of type new_type
.
[edit] Explanation
Only the following conversions can be done with const_cast. In particular, only const_cast may be used to cast away (remove) constness or volatility.
1) Two possibly multilevel pointers to the same type may be converted between each other, regardless of cv-qualifiers at each level.
2) lvalue of any type
T
may be converted to a lvalue or rvalue reference to the same type T
, more or less cv-qualified. Likewise, an rvalue may be converted to a more or less cv-qualified rvalue reference.
3) Same rules apply to possibly multilevel pointers to data members and possibly multilevel pointers to arrays of known and unknown bound (arrays to cv-qualified elements are considered to be cv-qualified themselves) (since C++17)
4) null pointer value may be converted to the null pointer value of new_type
As with all cast expressions, the result is:
- an lvalue if new_type is an lvalue reference type or an rvalue reference to function type;
- an xvalue if new_type is an rvalue reference to object type;
- a prvalue otherwise.
[edit] Notes
Pointers to functions and pointers to member functions are not subject to const_cast
[edit] Keywords
[edit] Example
Run this code
#include <iostream> struct type { type() :i(3) {} void m1(int v) const { // this->i = v; // compile error: this is a pointer to const const_cast<type*>(this)->i = v; // OK as long as the type object isn't const } int i; }; int main() { int i = 3; // i is not declared const const int& cref_i = i; const_cast<int&>(cref_i) = 4; // OK: modifies i std::cout << "i = " << i << '\n'; type t; // note, if this is const type t;, then t.m1(4); is UB t.m1(4); std::cout << "type::i = " << t.i << '\n'; const int j = 3; // j is declared const int* pj = const_cast<int*>(&j); *pj = 4; // undefined behavior! void (type::*mfp)(int) const = &type::m1; // pointer to member function // const_cast<void(type::*)(int)>(mfp); // compiler error: const_cast does not // work on function pointers }
Output:
i = 4 type::i = 4