std::max
From cppreference.com
Defined in header
<algorithm>
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(1) | ||
template< class T >
const T& max( const T& a, const T& b ); |
(until C++14) | |
template< class T >
constexpr const T& max( const T& a, const T& b ); |
(since C++14) | |
(2) | ||
template< class T, class Compare >
const T& max( const T& a, const T& b, Compare comp ); |
(until C++14) | |
template< class T, class Compare >
constexpr const T& max( const T& a, const T& b, Compare comp ); |
(since C++14) | |
(3) | ||
template< class T >
T max( std::initializer_list<T> ilist ); |
(since C++11) (until C++14) |
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template< class T >
constexpr T max( std::initializer_list<T> ilist ); |
(since C++14) | |
(4) | ||
template< class T, class Compare >
T max( std::initializer_list<T> ilist, Compare comp ); |
(since C++11) (until C++14) |
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template< class T, class Compare >
constexpr T max( std::initializer_list<T> ilist, Compare comp ); |
(since C++14) | |
Returns the greater of the given values.
1-2) Returns the greater of
a
and b
.
3-4) Returns the greatest of the values in initializer list
ilist
.The (1,3) versions use operator< to compare the values, the (2,4) versions use the given comparison function comp
.
Contents |
[edit] Parameters
a, b | - | the values to compare |
ilist | - | initializer list with the values to compare |
comp | - | comparison function object (i.e. an object that satisfies the requirements of Compare ) which returns true if if a is less than b . The signature of the comparison function should be equivalent to the following: bool cmp(const Type1 &a, const Type2 &b); The signature does not need to have const &, but the function object must not modify the objects passed to it. |
Type requirements | ||
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T must meet the requirements of LessThanComparable in order to use overloads (1,3).
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T must meet the requirements of CopyConstructible in order to use overloads (3,4).
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[edit] Return value
1-2) The greater of
a
and b
. If they are equivalent, returns a
.
3-4) The greatest value in
ilist
. If several values are equivalent to the greatest, returns the leftmost one.[edit] Complexity
1-2) Exactly one comparison
3-4) Exactly
ilist.size() - 1
comparisons[edit] Possible implementation
First version |
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template<class T> const T& max(const T& a, const T& b) { return (a < b) ? b : a; } |
Second version |
template<class T, class Compare> const T& max(const T& a, const T& b, Compare comp) { return (comp(a, b)) ? b : a; } |
Third version |
template< class T > T max( std::initializer_list<T> ilist) { return *std::max_element(ilist.begin(), ilist.end()); } |
Fourth version |
template< class T, class Compare > T max( std::initializer_list<T> ilist, Compare comp ) { return *std::max_element(ilist.begin(), ilist.end(), comp); } |
[edit] Notes
Capturing the result of std::max
by reference if one of the parameters is rvalue produces a dangling reference if that parameter is returned:
int n = 1; const int& r = std::max(n-1, n+1); // r is dangling
[edit] Example
Run this code
#include <algorithm> #include <iostream> #include <string> int main() { std::cout << "larger of 1 and 9999: " << std::max(1, 9999) << '\n' << "larger of 'a', and 'b': " << std::max('a', 'b') << '\n' << "longest of \"foo\", \"bar\", and \"hello\": " << std::max( { "foo", "bar", "hello" }, [](const std::string& s1, const std::string& s2) { return s1.size() < s2.size(); }) << '\n'; }
Output:
larger of 1 and 9999: 9999 larger of 'a', and 'b': b longest of "foo", "bar", and "hello": hello
[edit] See also
returns the smaller of the given values (function template) |
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(C++11)
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returns the larger and the smaller of two elements (function template) |
returns the largest element in a range (function template) |