Method `/()

Method `/

mixed `/(object arg1, mixed arg2)
mixed `/(mixed arg1, object arg2)
array(string) `/(string arg1, int arg2)
array(string) `/(string arg1, float arg2)
array(array) `/(array arg1, int arg2)
array(array) `/(array arg1, float arg2)
array(string) `/(string arg1, string arg2)
array(array) `/(array arg1, array arg2)
float `/(float arg1, int|float arg2)
float `/(int arg1, float arg2)
int `/(int arg1, int arg2)
mixed `/(mixed arg1, mixed arg2, mixed ... extras)

Description

Division/split.

Every expression with the / operator becomes a call to this function, i.e. a/b is the same as predef::`/(a,b).

Returns

If there are more than two arguments, the result will be `/(`/(arg1, arg2), @extras).

If arg1 is an object that implements lfun::`/(), that function will be called with arg2 as the single argument.

If arg2 is an object that implements lfun::``/(), that function will be called with arg1 as the single argument.

Otherwise the result will be as follows:

arg1 can have any of the following types:

string	arg2 can have any of the following types: int|float The result will be and array of arg1 split in segments of length arg2. If arg2 is negative the splitting will start from the end of arg1. string The result will be an array of arg1 split at each occurrence of arg2. Note that the segments that matched against arg2 will not be in the result.
array	arg2 can have any of the following types: int|float The result will be and array of arg1 split in segments of length arg2. If arg2 is negative the splitting will start from the end of arg1. array The result will be an array of arg1 split at each occurrence of arg2. Note that the elements that matched against arg2 will not be in the result.
float|int	The result will be arg1 / arg2. If both arguments are int, the result will be truncated to an int. Otherwise the result will be a float.

Note

Unlike in some languages, the function f(x) = x/n (x and n integers) behaves in a well-defined way and is always rounded down. When you increase x, f(x) will increase with one for each n:th increment. For all x, (x + n) / n = x/n + 1; crossing zero is not special. This also means that / and % are compatible, so that a = b*(a/b) + a%b for all a and b.

See also

`%