std::make_unsigned
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header  
<type_traits>
  | 
||
|   template< class T > 
struct make_unsigned;  | 
(since C++11) | |
If T is an integral (except bool) or enumeration type, provides the member typedef type which is the unsigned integer type corresponding to T, with the same cv-qualifiers.
Otherwise, the behavior is undefined.
Contents | 
[edit] Member types
| Name | Definition | 
  type
 | 
  the unsigned integer type corresponding to T
 | 
[edit] Helper types
|   template< class T > 
using make_unsigned_t = typename make_unsigned<T>::type;  | 
(since C++14) | |
[edit] Example
Run this code
#include <iostream> #include <type_traits> int main() { typedef std::make_unsigned<char>::type char_type; typedef std::make_unsigned<int>::type int_type; typedef std::make_unsigned<volatile long>::type long_type; bool ok1 = std::is_same<char_type, unsigned char>::value; bool ok2 = std::is_same<int_type, unsigned int>::value; bool ok3 = std::is_same<long_type, volatile unsigned long>::value; std::cout << std::boolalpha << "char_type is 'unsigned char'? : " << ok1 << '\n' << "int_type is 'unsigned int'? : " << ok2 << '\n' << "long_type is 'volatile unsigned long'? : " << ok3 << '\n'; }
Output:
char_type is 'unsigned char'? : true int_type is 'unsigned int'? : true long_type is 'volatile unsigned long'? : true
[edit] See also
|    (C++11) 
 | 
   checks if a type is signed arithmetic type   (class template)  | 
|    (C++11) 
 | 
   checks if a type is unsigned arithmetic type   (class template)  | 
|    (C++11) 
 | 
   makes the given integral type signed   (class template)  |