std::experimental::filesystem::path::root_path
From cppreference.com
                    
                                        
                    < cpp | experimental | fs | path
                    
                                                            
                    |   path root_path() const; 
 | 
(filesystem TS) | |
Returns the root path of the path. If the path does not include root path, returns path().
Effectively, returns the following: root_name() / root_directory()
Contents | 
[edit] Parameters
(none)
[edit] Return value
The root path of the path.
[edit] Exceptions
(none)
[edit] Example
Run this code
#include <iostream> #include <experimental/filesystem> namespace fs = std::experimental::filesystem; int main() { std::cout << "Current root path is: " << fs::current_path().root_path() << '\n'; }
Possible output:
Current root path is: "C:\"
[edit] See also
|    returns the root-name of the path, if present  (public member function)  | 
|
|    returns the root directory of the path, if present  (public member function)  |