std::fill_n
From cppreference.com
                    
                                        
                    
                    
                                                            
                    |   Defined in header  
<algorithm>
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|   template< class OutputIt, class Size, class T > 
void fill_n( OutputIt first, Size count, const T& value );  | 
(until C++11) | |
|   template< class OutputIt, class Size, class T > 
OutputIt fill_n( OutputIt first, Size count, const T& value );  | 
(since C++11) | |
Assigns the given value to the first count elements in the range beginning at first if count > 0. Does nothing otherwise.
Contents | 
[edit] Parameters
| first | - | the beginning of the range of elements to modify | 
| count | - | number of elements to modify | 
| value | - | the value to be assigned | 
| Type requirements | ||
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OutputIt must meet the requirements of OutputIterator.
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[edit] Return value
| (none) | (until C++11) | 
 Iterator one past the last element assigned if count > 0, first otherwise.
 | 
(since C++11) | 
[edit] Complexity
Exactly count assignments, for count > 0.
[edit] Possible implementation
template<class OutputIt, class Size, class T> OutputIt fill_n(OutputIt first, Size count, const T& value) { for (Size i = 0; i < count; i++) { *first++ = value; } return first; }  | 
[edit] Example
 The following code uses fill_n() to assign -1 to the first half of a vector of integers: 
 
Run this code
#include <algorithm> #include <vector> #include <iostream> #include <iterator> int main() { std::vector<int> v1{0, 1, 2, 3, 4, 5, 6, 7, 8, 9}; std::fill_n(v1.begin(), 5, -1); std::copy(begin(v1), end(v1), std::ostream_iterator<int>(std::cout, " ")); std::cout << "\n"; }
Output:
-1 -1 -1 -1 -1 5 6 7 8 9
[edit] See also
|    assigns a range of elements a certain value   (function template)  | 
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|    (parallelism TS) 
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   parallelized version of std::fill_n  (function template)  |