std::fill_n

From cppreference.com
< cpp‎ | algorithm
 
 
 
Defined in header <algorithm>
template< class OutputIt, class Size, class T >
void fill_n( OutputIt first, Size count, const T& value );
(until C++11)
template< class OutputIt, class Size, class T >
OutputIt fill_n( OutputIt first, Size count, const T& value );
(since C++11)

Assigns the given value to the first count elements in the range beginning at first if count > 0. Does nothing otherwise.

Contents

[edit] Parameters

first - the beginning of the range of elements to modify
count - number of elements to modify
value - the value to be assigned
Type requirements
-
OutputIt must meet the requirements of OutputIterator.

[edit] Return value

(none) (until C++11)
Iterator one past the last element assigned if count > 0, first otherwise. (since C++11)

[edit] Complexity

Exactly count assignments, for count > 0.

[edit] Possible implementation

template<class OutputIt, class Size, class T>
OutputIt fill_n(OutputIt first, Size count, const T& value)
{
    for (Size i = 0; i < count; i++) {
        *first++ = value;
    }
    return first;
}

[edit] Example

The following code uses fill_n() to assign -1 to the first half of a vector of integers:

#include <algorithm>
#include <vector>
#include <iostream>
#include <iterator>
 
int main()
{
    std::vector<int> v1{0, 1, 2, 3, 4, 5, 6, 7, 8, 9};
 
    std::fill_n(v1.begin(), 5, -1);
 
    std::copy(begin(v1), end(v1), std::ostream_iterator<int>(std::cout, " "));
    std::cout << "\n";
}

Output:

-1 -1 -1 -1 -1 5 6 7 8 9

[edit] See also

assigns a range of elements a certain value
(function template)
parallelized version of std::fill_n
(function template)